How many moles of O2 are in KClO3?
So, 6 moles of Oxygen Gas O2 has been given to you. To calculate the number of moles for potassium chlorate KClO3 , use the mole ratio.
How many moles of oxygen gas are produced by the decomposition of 245 g of potassium chlorate?
The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.
How many moles of O2 can be produced by letting 12 mol of KClO3 react in the following equation 2 KClO3 → 2 KCL 3 O2?
How many moles of O2 can be produced by letting 12.00 moles of KClO3 react? The KClO3 / O2 molar ratio is 2/3. 2 mol KClO3 / 3 mol. O2 = 12.00 mol KClO3 / x = 18.00 mol.
How many grams of O2 can be produced from heating KClO3?
Calculate how many grams of O2(g) can be produced from heating 36.1 grams of KClO3(s).? 0.442 mol O2 = 0.442*32 = 14.1g O2 will be produced. Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s).
How many moles of O2 are produced from 3.0 moles of kclo3?
The balanced equation tells us that we get 3 moles of O2 for every 2 moles of KClO3. (3/2)*(3.0) moles O2, or 4.5 moles of O2. Kaitlyn G.
How many moles of O2 are in 2 moles of kclo3?
According to the balanced reaction, the decomposition of two moles of potassium chlorate gives two moles of potassium chloride, and three moles of oxygen.
How many moles of oxygen are produced when 3.0 moles of KClO3 decomposes completely?
(3/2)*(3.0) moles O2, or 4.5 moles of O2.
How many moles of oxygen gas are produced from the decomposition of six moles of potassium chloride?
Explanation: From the equation, 32 equiv dixoygen gas evolve from 1 equiv chlorate. You started with 6 equiv chlorate, and thus 9 equiv dioxygen gas are evolved.
How many grams of O2 are produced?
The mass of O2 is [18 moles × 32 g/mol] = 576 grams. Overall, 12 moles of NaClO3 will produce 576 grams of O2.
How many grams of O2 are produced from 3 moles KClO3?
110.88 g of oxygen is produced.
How many grams of oxygen are produced in 1mol of KClO3?
5.00g 2KClO3 ⋅ 1mol 2KClO3 122.55g 2KClO3 ⋅ 3mol O2 2mol 2KClO3 ⋅ 16.00g O2 1mol O2 = 1.96g O2
How many grams of O2 in 2 KCl?
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn’t matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl.
How to calculate the yield of potassium chlorate?
So, if absolutely every mole of potassium chlorate that decomposes upon heating ends up producing 3 2 moles of oxygen gas, then the reaction is said to have a 100% yield → this will be your theoretical yield. Use potassium chlorate’s molar mass to determine how many moles you have in that 19.45-g sample
What happens when potassium chlorate is heated to form KCl?
Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.