## How many moles of O2 are in KClO3?

6 moles

So, 6 moles of Oxygen Gas O2 has been given to you. To calculate the number of moles for potassium chlorate KClO3 , use the mole ratio.

**How many moles of oxygen gas are produced by the decomposition of 245 g of potassium chlorate?**

The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.

### How many moles of O2 can be produced by letting 12 mol of KClO3 react in the following equation 2 KClO3 → 2 KCL 3 O2?

How many moles of O2 can be produced by letting 12.00 moles of KClO3 react? The KClO3 / O2 molar ratio is 2/3. 2 mol KClO3 / 3 mol. O2 = 12.00 mol KClO3 / x = 18.00 mol.

**How many grams of O2 can be produced from heating KClO3?**

Calculate how many grams of O2(g) can be produced from heating 36.1 grams of KClO3(s).? 0.442 mol O2 = 0.442*32 = 14.1g O2 will be produced. Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s).

#### How many moles of O2 are produced from 3.0 moles of kclo3?

The balanced equation tells us that we get 3 moles of O2 for every 2 moles of KClO3. (3/2)*(3.0) moles O2, or 4.5 moles of O2. Kaitlyn G.

**How many moles of O2 are in 2 moles of kclo3?**

According to the balanced reaction, the decomposition of two moles of potassium chlorate gives two moles of potassium chloride, and three moles of oxygen.

## How many moles of oxygen are produced when 3.0 moles of KClO3 decomposes completely?

(3/2)*(3.0) moles O2, or 4.5 moles of O2.

**How many moles of oxygen gas are produced from the decomposition of six moles of potassium chloride?**

Explanation: From the equation, 32 equiv dixoygen gas evolve from 1 equiv chlorate. You started with 6 equiv chlorate, and thus 9 equiv dioxygen gas are evolved.

### How many grams of O2 are produced?

576 grams

The mass of O2 is [18 moles × 32 g/mol] = 576 grams. Overall, 12 moles of NaClO3 will produce 576 grams of O2.

**How many grams of O2 are produced from 3 moles KClO3?**

110.88 g of oxygen is produced.

#### How many grams of oxygen are produced in 1mol of KClO3?

5.00g 2KClO3 ⋅ 1mol 2KClO3 122.55g 2KClO3 ⋅ 3mol O2 2mol 2KClO3 ⋅ 16.00g O2 1mol O2 = 1.96g O2

**How many grams of O2 in 2 KCl?**

2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn’t matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl.

## How to calculate the yield of potassium chlorate?

So, if absolutely every mole of potassium chlorate that decomposes upon heating ends up producing 3 2 moles of oxygen gas, then the reaction is said to have a 100% yield → this will be your theoretical yield. Use potassium chlorate’s molar mass to determine how many moles you have in that 19.45-g sample

**What happens when potassium chlorate is heated to form KCl?**

Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.